A solid sphere rolling on a rough horizontal surface with a linear speed v collides elastically with a fixed, smooth vertical wall. Find the speed of the sphere after it has began pure rolling in the backward direction.
A
B
C
D
None
Text Solution
Verified by ExpertsThe correct answer is:
B
F f r = I α α = 
α α = 
after collision
v f = v- 
……….. (i)
ω ω f = - ω ω + α α t= - ω ω + 
.
or r ω ω f = - r ω ω + 
t
or v f = - v + 
……….. (ii)
From eq. (i) and (ii)
v f = - v + 
(v – v f ) or v f = 
v.
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